4 (2x-7) =5 and check the result
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Answered by
1
4 (2x-7) = 5
8x-28=5
8x=5+28
8x=33
x=33/8
so, 4(2×33/8-7)=5
4 (33/4-7)=5
4 {( 33-28)/4}=5
4×5/4 = 5
5=5
8x-28=5
8x=5+28
8x=33
x=33/8
so, 4(2×33/8-7)=5
4 (33/4-7)=5
4 {( 33-28)/4}=5
4×5/4 = 5
5=5
sakshi4664:
check the result
where did the 28
I checked the result
you add, multiple , subtract division
4(2x-7)=5. so, 4(2×33/8-7)=5. ,4×5/4=5. 5=5. i kept 33/8 at the place of x.
Answered by
0
4(2x-7)=5
8x-28=5
8x=5+28
8x=33
x=33\8
x=4.125
—————————-
Verification
LHS= 4(2x-7)
RHS=5
substitute x in LHS
4( 2*4.125-7)
4( 8.25-7)
4*1.25
=5
; LHS=RHS
Verified
8x-28=5
8x=5+28
8x=33
x=33\8
x=4.125
—————————-
Verification
LHS= 4(2x-7)
RHS=5
substitute x in LHS
4( 2*4.125-7)
4( 8.25-7)
4*1.25
=5
; LHS=RHS
Verified
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