Question

(4)^-3 ×__________=1/16​

Answer 1

$\huge\qquad \mathbb{\fcolorbox{red}{lavenderblush}{✰Answer}}$

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Given that,

$\tt{(4)^{-3}×--=\dfrac{1}{16}   }$ 

We have to find the value of the bracket place.

Let the bracket place is X

According to the question ,

• $\sf{ (4)^{-3}×X=\dfrac{1}{16}}$

• $\sf{\dfrac{1}{(4)^{3}}×X=\dfrac{1}{16}}$

• $\sf{\dfrac{1}{64}×X=\dfrac{1}{16}}$

• $\sf{X=\dfrac{1}{16}×\dfrac{64}{1}}$

• $\sf{\red{X=4}}$ 

So,

The bracket value is 4

$\therefore{ (4)^{-3}×\underline{4}=\dfrac{1}{16}}$ 

 

$\sf{\color{aquamarine}{@Smaranika54}}$

Answer 2

Step-by-step explanation:

4^-3__________=1/16

1/4^3x a=1/16

a=1/16x64

a=4