Question

(4√3-2√2) (3√2+4√3)​

Answer 1

Answer:

[1] = (4√3) / (2-√2) = (4√3)(2+√2) / (2-√2)(2+√2)

= (8√3+4√6) /2

= 4√3+2√6 …………………(1)

[2]= 30 / (4√3-√18)

= 30*(4√3+√18) /(4√3-√18)(4√3+√18)

=( 120√3 +30√18) /(48–18)

= 30(4√3+√18) /30

= 4√3 + 3√2 ………………(2)

[3]= √18 / (3–2√3)

= √18(3+2√3) / (3–2√3) (3+2√3)

= (3√18+2√54) /9–12

= (9√2 + 6√6) /-3

= -3√2 -2√6 ………………(3)

Now by combining all 3 terms:

(4√3+2√6) — (4√3+3√2) — ( -3√2 -2√6)

= 4√3+2√6–4√3–3√2+3√2+2√6

= 2√6 + 2√6

= 4√6 ………….ANS

Answer 2

Answer:

i sloved your question but before you mark me as brainlist ....

then I solved it ..

plzzzz Kar do yarrr !!!!

I need only 2 mark plzzz Kar do