Question

4/ √3 + 2√2 rationalise the denominator

Answer 1

Answer:

this is the answer hope it helps to you

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Answer 2

Answer:

$\frac{4}{ \sqrt{3} + 2 \sqrt{2} }$

$= \frac{4}{ (\sqrt{3} + 2 \sqrt{2} )} \times \frac{(\sqrt{3} - 2 \sqrt{2} )}{(\sqrt{3} - 2 \sqrt{2} )}$

$= \frac{4(\sqrt{3} - 2 \sqrt{2} )}{ ({ \sqrt{3} )}^{2} - {(2 \sqrt{2} )}^{2} }$

$= \frac{4(\sqrt{3} - 2 \sqrt{2} )}{3 - 8}$

$= \frac{4(\sqrt{3} - 2 \sqrt{2} )}{ - 5}$

$= \frac{4(\sqrt{3} - 2 \sqrt{2} )}{5}$