Math, asked by jyotiwagh, 8 months ago

4+√3/2+√3 (rationalise the denominator)

Answers

Answered by Anonymous
3

Answer:

 \frac{4 +  \sqrt{3} }{2 +  \sqrt{3} }  \times  \frac{2 -  \sqrt{3} }{2 -  \sqrt{3} } \\  \frac{(4 +  \sqrt{3} )(2 -  \sqrt{3}) }{ {(2)}^{2}  -  {( \sqrt{3} )}^{2} }   \\  \frac{8 - 4 \sqrt{3}  + 2 \sqrt{3}  - 3}{4 - 3}  \\  \frac{5 - 2 \sqrt{3} }{1}

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