Question

ɢɪᴠᴇɴ ᴛᴀɴ ᴀ = 4/3, ꜰɪɴᴅ (ᴄᴏꜱᴇᴄ ᴀ)/(ᴄᴏꜱ ᴀ-ꜱᴇᴄ ᴀ)​
ᴩʟꜱ ᴀɴꜱ
ɪʟʟ ɢɪᴠᴇ ʙʀᴀɪɴᴇꜱᴛ​

Answer 1

Tan A = 4/3 = BC/AB

Let BC be 4x and AB be 3x,

AC² = BC²+AB²

AC² = (4x)² + (3x)²

AC² = 16x² + 9x²

AC² = 25x²

AC = 5x

Cosec A = AC/BC = 5/4

Cos A = AB/AC = 3/5

Sec A = AC/AB = 5/3

(Cosec A)/(Cos A - Sec A) = 5/4 ÷ (3/5-5/3) = 5/4 ÷ -16/15 = 5/4×-15/16 = -75/64

Hope it helps!!

Thank you ✌️

Answer 2

hope it helps ✌️✌️✌️✌️