Question

⁴⁄₃ ( 2x + 1 ) + 7 ≤ 3 + ⁵⁄₂ ( x + 2 ) , x ∈ Q
Find Solution set of the above equation.

Answer 1

Given :-

→ ⁴⁄₃ ( 2x + 1 ) + 7 ≤ 3 + ⁵⁄₂ ( x + 2 ) , x ∈ Q

To find :-

→ Solution Set

Solution :-

→ ⁴⁄₃ ( 2x + 1 ) + 7 ≤ 3 + ⁵⁄₂ ( x + 2 )

→ 8 ( 2x + 1) + 42 ≤ 18 + 15 ( x + 2)

✯Multiply both sides by 6, the L.C/M of 3 and 2✯

→ 16x + 8 + 42 ≤ 18 + 15 ( x + 2)

→ 16x + 50 ≤ 15x + 48

✯Subtracting 50 and 15x from both the sides✯

→ 16x ≤ 15x - 2

→ x ≤ -2

∴ The solution Set :-

• { x ∈ Q: x ≤ -2}

Answer 2

Answer:

⁴⁄₃ ( 2x + 1 ) + 7 ≤ 3 + ⁵⁄₂ ( x + 2 )

→ 8 ( 2x + 1) + 42 ≤ 18 + 15 ( x + 2)

✯Multiply both sides by 6, the L.C/M of 3 and 2✯

→ 16x + 8 + 42 ≤ 18 + 15 ( x + 2)

→ 16x + 50 ≤ 15x + 48

✯Subtracting 50 and 15x from both the sides✯

→ 16x ≤ 15x - 2

→ x ≤ -2

∴ The solution Set :-

{ x ∈ Q: x ≤ -2}

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