Question

(4)
3.
(3) -4 m/s
The velocity of a particle is given by the equa-
tion, v=2t2 + 5 cms-1. The average acceleration
during the interval t; = 2s and t = 4s is
(1) 6 cms-2
(2) 12 cms-2
18 cms-2
(4) 24 cms-2
(3)
article is​

Answer 1

Correct option is

D

14 m/s

2

Velocity when t=2s is v

2

=10+2×4=18m/s

Velocity when t=5s is v

5

=10+2×25=60m/s

so change in velocity will be Δv=60−18=42m/s

time taken is Δt=5−2=3s

so the average acceleration will be a=

Δt

Δv

=

3s

42m/s

=14m/s

2