Question

[(4/3)^3+(7/5)^-2]x(2/7)^-2 simplify​

Answer 1

Answer:

${ \frac{4}{3} }^{3} + { \frac{7}{5} }^{ - 2} \times { \frac{2}{7} }^{ - 2} = { \frac{4}{3} }^{3} + ({ \frac{7}{5} \times \frac{2}{7} })^{ - 2} = { \frac{4}{3} }^{3} + { \frac{2}{5} }^{ - 2} = { \frac{4}{3} }^{3} + { \frac{5}{2} }^{2} = \frac{64}{27} + \frac{25}{4} = \frac{256}{108} + \frac{150}{108} = \frac{406}{108}$

\frac{4}{3} }^{3}