Question

4×3+4÷90×5÷33×3×94(2+9÷345)​

Answer 1

Answer:

15.8475186649

Explanation:

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Answer 2

Answer is

$\huge{\boxed{ \bold{ \fcolorbox{pink}{yellow}{67.92}}}}$

$\pink{ \bold{ \underline {\underline{Step \: by \: step \: explanation:}}}}$

$4 \times 3 + 4 \div 90 \times 5 \div 33 \times 3 \times 99(2 + 9 \div 345) \\ \\ \bold{by \: BODMAS \: rue} \\\\ 12 + \frac{2}{25} \times \frac{5}{33} \times 3 \times 99(2 + \frac{3}{115} ) \\\\ = 12 + \frac{2}{25} \times \frac{5}{11} \times 99( \frac{230 + 3}{15} )\\ \\ = 12 + \frac{2}{5} \times \frac{1}{11} \times 99 \times \frac{233}{15} \\ \\ = 12 + \frac{2}{5} \times 9 \times \frac{233}{15} \\ \\ = 12 + \frac{2}{5} \times 3 \times \frac{233}{5} \\ \\ = 12 + \frac{6 \times 233}{5 \times 5} = 12 + \frac{1398}{25} \\ \\ = \frac{300 + 1398}{25} = \frac{1698}{25} \\ \\ =\huge{67.92}$

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