Question

4 - 3 बार 5 डिवाइडेड बाय 4 -​

Answer 1

Answer Text

110

25

710

none of these

Answer :

A

Solution :

Let E1,E2 and E3 be the events that A ,B and C can hit respectively .

Then P(E1)=45P(E2)=34 and P(E3)=23

Pequired probability = P(E2 and E3 but not E1)=P(E2)×P(E3)×P(E1)  

={34×23×(1−45)}=(12×15)=110