Computer Science, asked by franciscoluke55613, 11 months ago

4.3 code practice edhesive (in python 3) write a program that uses a loop to print the uppercase alphabet with the correct ASCII number next to each letter. (e.g., one line might be A 65).

Answers

Answered by BrainlyYoda
3

Answer:

x = 64

while x >= 64 and x <= 89:

                       x =x+ 1

                       print(str(chr (x))+ "=> ASCII number is = " +  str(x))

Output:

A=> ASCII number is = 65

B=> ASCII number is = 66

C=> ASCII number is = 67

D=> ASCII number is = 68

E=> ASCII number is = 69

F=> ASCII number is = 70

G=> ASCII number is = 71

H=> ASCII number is = 72

I=> ASCII number is = 73

J=> ASCII number is = 74

K=> ASCII number is = 75

L=> ASCII number is = 76

M=> ASCII number is = 77

N=> ASCII number is = 78

O=> ASCII number is = 79

P=> ASCII number is = 80

Q=> ASCII number is = 81

R=> ASCII number is = 82

S=> ASCII number is = 83

T=> ASCII number is = 84

U=> ASCII number is = 85

V=> ASCII number is = 86

W=> ASCII number is = 87

X=> ASCII number is = 88

Y=> ASCII number is = 89

Z=> ASCII number is = 90

This code is written in Python Programming Language.

We have taken a variable x and assigned value 64 because 65 is ASCII value of A and to run it in a loop so, it can print till Z along with its ASCII values.

Note=> Indentation is important.

Answered by Anonymous
2

Answer:

Answer:x = 64 while x >= 64 and x <= 89: x =x+ 1 print(str(chr (x))+ "=> ASCII number is = " + str(x)) Output:A=> ASCII number is = 65 B=> ASCII number ..

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