4/3 cot²30 + 2sin²60 - 2 cosec²60 - 3/4 tan²30
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Answered by
2
cot 30=√3
sin 60=√3/2
cosec 60=2/√3
tan 30=1/√3
4/3 cot²30 + 2 sin²60 - 2 cosec²60 - 3/4 tan²30
=4/3 ×(√3)² + 2×(√3/2)² - 2×(2/√3)² - 3/4 ×( 1/√3)²
=4/3×3 +2×3/4 - 2×4/3 - 3/4×1/3
=4 +3/2 - 8/3 - 1/4
=4+18-32-3/12
=22-35/12
= - 13/12
i think the answer is correct
sin 60=√3/2
cosec 60=2/√3
tan 30=1/√3
4/3 cot²30 + 2 sin²60 - 2 cosec²60 - 3/4 tan²30
=4/3 ×(√3)² + 2×(√3/2)² - 2×(2/√3)² - 3/4 ×( 1/√3)²
=4/3×3 +2×3/4 - 2×4/3 - 3/4×1/3
=4 +3/2 - 8/3 - 1/4
=4+18-32-3/12
=22-35/12
= - 13/12
i think the answer is correct
ammunazriya:
ya
why are you interested in my answer
vignesh and i got the same answer and his teacher told that it is wrong
so u r only left
then my answer was wrong
then wat is the answer
hmm
no one knows
hahaha
Hmm
Answered by
2
cot 30=√3
sin 60=√3/2
cosec 60=2/√3
tan 30=1/√3
4/3 cot²30 + 2 sin²60 - 2 cosec²60 - 3/4 tan²30
=4/3 ×(√3)² + 2×(√3/2)² - 2×(2/√3)² - 3/4 ×( 1/√3)²
=4/3×3 +2×3/4 - 2×4/3 - 3/4×1/3
=4 +3/2 - 8/3 - 1/4
=4+18-32-3/12
=22-35/12
= - 13/12.
Hope it helps you ❤️
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