Question

4+3 root5 ÷ 4- 3 root5 rationalise it

Answer 1

the answer of this question is

Answer 2

$\frac{4 + 3\sqrt{5} }{4- 3 \sqrt{5} }$

Rationalization,

$\frac{4+ 3 \sqrt{5} }{4 - 3 \sqrt{5} }$× $\frac{4+3 \sqrt{5} }{4 + 3\sqrt{5} }$

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On nominator,
By Formula  $(a+b)^2 = a^2 + b^2 + 2ab$
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On Denominator
By Formula $a^2 -b^2 =(a+b)(a-b)$
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Now,

$\frac{(4+3 \sqrt{5})^2 }{(4)^2 - (3 \sqrt{5})^2 }$


$\frac{16 + 45 + 6 \sqrt{5} }{16 - 45 }$

$\frac{61 + 6 \sqrt{5} }{-29}$




i hope this will help you


-by ABHAY