Question

4আত্মসফিয়ার চাপে ও 300k উষ্ণতায় 8g H² গ্যাসের (H=1) আয়তন কত হবে? (R=0.082 লিটার আত্মসফিয়ার মোল- 1 K-1)
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Answer 1

Answer:

Step-by-step explanation:

We are going to use the ideal gas law, which states that

PV=nRT

P is pressure in pascals (Pa)

V is volume in m3

n is the number of moles of the substance

R is the gas constant

T is the temperature in Kelvin (K)

Since we are using atmospheric pressure as units and the gas constant as

0.082

Lit−atm−mol−1K−1

, then our volume will be in liters (l)

So, plugging in P=4atm ,

n = 8g ÷ 2.016g/mol ≈ 3.97mol ,

R = 0.082

and

T = 300 K

we get

V = (n R T)/P =( 3.97 × 0.082×300)/4 ≈ 24.42 l = 24420 cm3 of hydrogen gas (H2)