Math, asked by kdani9486, 4 months ago

(4+3i) (4-3i) where i=iota

Answers

Answered by usernametaken8

0

Answer:

19

Step-by-step explanation:

(4+3i)(4-3i)= 16 - 3i² = 16 +3 (i²= -1)

=19

Answered by hassanalihassanali06

4

Answer:

I=√-1

4^2+3^2u^2

16+9= 25 ans

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