(4-3i)power -1 simplify and express each of following
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this is the answer.....................
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akjha72:
thanks bhaijaan
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( 4 - 3 i )^-1
= 1 / 4 - 3i
by rationalising denominator , we get
= 1 /( 4 - 3i ) × ( 4 + 3i ) / 4 + 3i
= 4 + 3i / ( 4 )^2 - ( 3i )^2
= 4 + 3i / 16 - 9 i^2
since , we know that , i^2 = - 1
therefore ,
= 4 + 3i / 16 - 9 ( - 1)
= 4+ 3i / 16 + 9
= 4 + 3i / 25
= 4 / 25 + 3i / 25
= 4 /25 + (3 / 25)i
= a + b i
= 1 / 4 - 3i
by rationalising denominator , we get
= 1 /( 4 - 3i ) × ( 4 + 3i ) / 4 + 3i
= 4 + 3i / ( 4 )^2 - ( 3i )^2
= 4 + 3i / 16 - 9 i^2
since , we know that , i^2 = - 1
therefore ,
= 4 + 3i / 16 - 9 ( - 1)
= 4+ 3i / 16 + 9
= 4 + 3i / 25
= 4 / 25 + 3i / 25
= 4 /25 + (3 / 25)i
= a + b i
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