Question

(4/3m-3/4n)^22mn=16/9m^2+9/16n^2​

Answer 1

Answer :-

LHS :-

$( \frac{4}{3} m - \frac{3}{4} \: n) ^{2} + 2mn \\ \\ = (\frac{4}{3}m)^{2} - 2( \frac{4}{3}m)( \frac{3}{4}n) +( \frac{3}{4}n)^{2} + 2mn \\ \\ = \frac{16}{9} {m}^{2} - 2mn + \frac{9}{16} {n}^{2} + 2mn \\ \\ = \frac{16}{9} {m}^{2} + \frac{9}{16} {n}^{2} = r.h.s$

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