Question

4(3n+4)+5(4n-3)=7(n-5)+32 solve the following equation​

Answer 1

Answer:

4(3n+4)+5(4n-3) = 7(n-5)+32

=>12n+16+20n-15 = 7n-35+32

=>32n+1 = 7n-3

=>32n-7n = -3-1

=>25n = -4

=>n = -4/25