Question

4/3root3-2root2+3/3root3+2root2​

Answer 1

Step-by-step explanation:

Question:-

$\frac{4}{3 \sqrt{3} } - 2 \sqrt{2} + \frac{3}{3 \sqrt{3} } + 2 \sqrt{2}$

solution:-

$\frac{4}{3 \sqrt{3} } - 2 \sqrt{2} + \frac{3}{3 \sqrt{3} } + 2 \sqrt{2}$

$\frac{4}{3 \sqrt{3} } + \frac{3}{3 \sqrt{3} } \\ \frac{7}{3 \sqrt{3} }$

now using rationalization

$\frac{7}{3 \sqrt{3} } \times \frac{3 \sqrt{3} }{3 \sqrt{3} } \\ \frac{21 \sqrt{3} }{9 \times 3} \\ \frac{7 \sqrt{3} }{9}$

answer:-

$\frac{7 \sqrt{3} }{9}$

Answer 2

Step-by-step explanation:

4 / 3√3 - 2√2+3 / 3√3+2√2

= 4 / 3√3 - 3 / 3√3

= 4-3 / 3√3

1 / 3√3

you can rationalise it further