4√3x^2-16x+5√3 factorise
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Answer:
Explanation:
Factorise into
(
3
x
−
1
)
(
x
−
5
)
=
0
For the left hand side to be zero, the contents of one of the brackets must evaluate to zero, hence
3
x
−
1
=
0
⇒
x
=
1
3
or
x
−
5
=
0
⇒
x
=
5
.
Alternatively you can use the quadratic formula for equations of the from
a
x
2
+
b
x
+
c
=
0
x
=
−
b
±
√
b
2
−
4
a
c
2
a
So in this case, a = 3, b = -16 and c = 5.
x
=
16
+
√
256
−
60
6
or
16
−
√
256
−
60
6
∴
x
=
5
or
x
=
1
3
u can solve like this
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