Question

(4-3x)^2
find the square​

Answer 1

ANSWER :-

$</p><p>\black{\boxed{\bold{(a-b)^2=a^2+b^2-2ab}}}$

$( {4 - 3x})^{2}$

$= {4}^{2} + ({3x})^{2} - 2 \times 4 \times 3x$

$= 9 {x}^{2} - 24x + 16.....ans$

HOPE IT WILL HELP U..

$</p><p>\blue{\bold{THANKS!}}$

Answer 2

Step-by-step explanation:

(4-3x)^2=4^2+(3x)^2-2.4.3x

16+9x^2-24x=0

9xl^2-12x-12x+16=0

x=4/3