Math, asked by sardarparimal014, 4 months ago

(4/3x^2yz)×(1/3y^2zx)×(-6xyz^2)

Answers

Answered by prasadderangula0110
0

Answer:

-8/3x^3y^3z^3

Step-by-step explanation:

check photo

Attachments:
Answered by amitnrw
1

Given : (4/3x²yz)×(1/3y²zx)×(-6xyz²)

To Find : Simplify the expression

Solution:

xᵃ * xᵇ = xᵃ⁺ᵇ

1/xᵃ  = x⁻ᵃ

(4/3x²yz)×(1/3y²zx)×(-6xyz²)

= { (4 * (-6))/ ( 3 * 3) } (1/x²yz)×(1/y²zx)×(xyz²)

= (-8/3)  ( x⁻²y⁻¹z⁻¹)×( y⁻²z⁻¹x⁻¹)×(xyz²)

= (-8/3)  ( x⁻²⁻¹⁺¹y⁻¹⁻²⁺¹z⁻¹⁻¹⁺²)

= (-8/3)  ( x⁻²y⁻²z⁰)

z⁰ = 1

= (-8/3)  ( x⁻²y⁻²)

=  (-8/3)  (1/ x²y²)

= - 8/(3x²y²)

(4/3x²yz)×(1/3y²zx)×(-6xyz²)  = - 8/(3x²y²)

Learn More :

find the value of - 34-3(-10)Simplify the following expressions and ...

brainly.in/question/23514927

Owen simplified the expression r-8 s-5. r−8s−5 = 1 r8 ⋅ s5 = s5 r8

brainly.in/question/13444792

Similar questions