Question

(4/3x^2yz)×(1/3y^2zx)×(-6xyz^2) multifly the questions ​

Answer 1

$Given \: \Big(\frac{4}{3} x^{2}yz\Big) \times \Big(\frac{1}{3} y^{2}zx\Big) \times </p><p>\Big(-6xyz^{2}\Big)$

$= \frac{4}{3} \times \frac{1}{3} \times (-6) \times x^{2} \times x \times x \times y \times y^{2} \times y \times z \times z \times z^{2}$

$= \frac{-8}{3} \times x^{2+1+1}\times y^{1+2+1} \times z^{1+1+2}$

$= \frac{-8}{3} x^{4}y^{4}z^{4}$

Therefore.,

$\red{\Big(\frac{4}{3} x^{2}yz\Big) \times \Big(\frac{1}{3} y^{2}zx\Big) \times </p><p>\Big(-6xyz^{2}\Big)}$

$\green{ = \frac{-8}{3} x^{4}y^{4}z^{4}}$

•••♪

Answer 2

$\bf{\underline{\underline{\bigstar\bigstar\: Solution }}}$

$\:$

$\Big(\frac{4}{3}x^2 yz\Big)×\Big(\frac{1}{3}y^2 zx\Big)×\Big(-6xy z^2\Big)$

$= \frac{4}{3} \times \frac{1}{3} \times (-6) \times x \times x \times x \times x \times y \times y \times y \times y \times z \times z \times z \times z$

$= \frac{-24}{9} \times x^4 \times y^4 \times z^4$

$= \frac{-8}{3} \times x^4 \times y^4 \times z^4$

$= \frac{-8}{3}x^4 y^4z^4$