Question

4√3x square + 5x - 2√3 = 0

Answer 1

Answer:

facteorise

Step-by-step explanation:

$4 \sqrt{3} {}^{2} + 5x - 2 \sqrt{3}$

4

*2*3. (

$(\sqrt{3 \times \sqrt{3} } )$

24

so we need to split in a way that sum be 5x and peoduct be 24 so 8x and (-3x)

4root3^2 +8x -3x+2root3

4root3^2 +8x -3x+2root3

4√3 x² +5x -2√3 =0

4root3^2 +8x -3x+2root3

4√3 x² +5x -2√3 =0

⇒4√3 x² +8x -3x-2√3=0

4root3^2 +8x -3x+2root3

4√3 x² +5x -2√3 =0

⇒4√3 x² +8x -3x-2√3=0

⇒4x(√3 x+2) -√3(√3x +2) =0

4root3^2 +8x -3x+2root3

4√3 x² +5x -2√3 =0

⇒4√3 x² +8x -3x-2√3=0

⇒4x(√3 x+2) -√3(√3x +2) =0

⇒(√3x +2)(4x -√3)=0

⇒(√3x +2) =0 or (4x-√3)=0

⇒x=-2/√3 or √3/4

hope u got it mark me brainlist