Question

(4\3x✓yz)×(1/3y✓zx)×(-6xyz✓)​

Answer 1

Answer:

4/3×1/3×-6 × x.y.z.√xy.√yz.√zx

=>-8/3.x²y²z²

Answer 2

Answer:

\:

\Big(\frac{4}{3}x^2 yz\Big)×\Big(\frac{1}{3}y^2 zx\Big)×\Big(-6xy z^2\Big)

( 34 x 2 yz)×( 3 y2zx)×(−6xyz 2 )

= \frac{4}{3} \times \frac{1}{3} \times (-6) \times x \times x \times x \times x \times y \times y \times y \times y \times z \times z \times z \times

z= 34 × 31

×(−6)×x×x×x×x×y×y×y×y×z×z×z×z

= \frac{-24}{9} \times x^4 \times y^4 \times

z^4= 9−24 ×x 4 ×y 4 ×z 4

= \frac{-8}{3} \times x^4 \times y^4 \times

z^4= 3−8 ×x 4 ×y 4 ×z 4

= \frac{-8}{3}x^4 y^4z^4= 3−8 x 4 y 4 z 4