4√3x²+4√3x-3√3 middle term
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√3(4x2+4x-3)=0
√3(4x2+6x-2x-3)=0
√3(2x(2x+3)-(2x+3))=0
(2x+3)√3=0
x=3/2√3
or
(2x-1)√3=0
x=1/2√3
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