Math, asked by singhruby94310, 8 months ago

4√3x²+5x-7√3 please solve it​

Answers

Answered by singhamanpratap0249
40

Answer:

4 \sqrt{3}  {x}^{2}  + 5x - 7 \sqrt{3}

4 \sqrt{3}  {x}^{2}  + 12x - 7x - 7 \sqrt{3}

4 \sqrt{3} x( x +  \sqrt{3} ) - 7(x +  \sqrt{3} )

(x +  \sqrt{3} )(4 \sqrt{3} x - 7)

Answered by choudharyadarsh777
1

Step-by-step explanation:

4✓3x^2+12x-7x-7✓3=0

4✓3x(x+✓3)-7(x+✓3)=0

(4✓3x-7)(x+✓3)=0

x= -✓3,

x= 7/4✓3 =7✓3/12(multiply ✓3 in Nr. and Dr.)

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