Question

(4/3x²yz)*(1/3y²zx)*(-6xyz²)

Answer 1

$\red{ Product \:of \: \Big(\frac{4}{3} x^{2}yz\Big)\Big(\frac{1}{3} y^{2}zx\Big)\Big( xyz^{2}\Big)}$

$= \frac{4}{3} \times \frac{1}{3} \times (-6) \times x^{2}\times x \times x \times y \times y^{2} \times y \times z \times z \times z^{2}$

$= \frac{-8}{3} \times x^{2+1+1} \times y^{1+2+1} \times z^{1+1+2}$

/* By Exponential Law */

$\boxed{\pink{ a^{m} \times a^{n} = a^{m+n} }}$

$= \frac{-8}{3} x^4y4z^4$

Therefore.,

$\red{ Product \:of \: \Big(\frac{4}{3} x^{2}yz\Big)\Big(\frac{1}{3} y^{2}zx\Big)\Big( xyz^{2}\Big)}$

$\green { = \frac{-8}{3} x^4y4z^4 }$

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