(4/3x2yz) ×(1/3y2zx)×(-6xyz2)
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Now we have given three terms: (4/3x^2yz) × (1/3y^2zx) × (-6xyz^2)
Taking the terms common, we get:
xyz ( 4x/3 × y/3 × -6z )
xyz ( -24 xyz / 9 )
xyz ( -8 xyz / 3 )
-8 x²y²z² / 3
So the product of given terms is -8 x²y²z².
Answer by @Krishhhhnna
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