Question

–⁴/³xy³ by ⁶/7x²y and verfiy your result x=2 any y=1​

Answer 1

answer here :-

To divide (-4/3xy³) by (6/7x²y), we can simplify the expression by multiplying the numerator by the reciprocal of the denominator:

(-4/3xy³) ÷ (6/7x²y) = (-4/3xy³) * (7x²y/6)

When we multiply fractions, we multiply the numerators and denominators separately:

((-4) * (7) * (x) * (x²) * (y) * (y)) / ((3) * (x) * (y³) * (6))

Simplifying further:

(-28x³y²) / (18xy³)

We can cancel out common factors in the numerator and denominator:

(-14x²) / (9y)

Now, let's verify this result by substituting x = 2 and y = 1:

(-14(2)²) / (9(1))

(-14 * 4) / 9

-56 / 9

Therefore, when x = 2 and y = 1, the value of the expression (-4/3xy³) ÷ (6/7x²y) is -56/9.