Question

(4-3y)^2 plz answer fast

Answer 1

Step-by-step explanation:

by the identity,

${(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2}$

let us take,

a=4 and b=3y

then we have,

$\: \: \: \: \: \: \: \: \: \: \: \: {(4 - 3y)}^{2} = {4}^{2} - 2(4)(3y) + {(3y)}^{2} \\ {(4 - 3y)}^{2} = 16 - 24y + 9 {y}^{2} \\ {(4 - 3y)}^{2} = 9 {y}^{2} - 24y + 16$

Hope it helps you....

Answer 2

(4-3y)² = 4² - 2(4)(3y) + (3y)²

           = 16 - 24y + 9y²

(4-3y)² = 16 - 24y + 9y²