Question

4√-4 +5√-9 -3√-16 answers​

Answer 1

Answer:

11√-1

Step-by-step explanation:

u need to know complex no. s

as √-1=iota

replace √-1=x or iota and just add and subtract

Answer 2

$\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Complex Numbers and Iota

since here, we know that,

$\sqrt{ - 1} = i$

so we can apply it here, here 'i' = iota

so we get as,

$4 \sqrt{ - 1 \times 4} + 5 \sqrt{ - 1 \times 9} - 3 \sqrt{ - 1 \times 16}$

solving futher we get as,

$4 \times 2 \sqrt{ - 1} + 5 \times 3 \sqrt{ - 1 } - 3 \times 4 \sqrt{ - 1}$

=>

8i + 15i -12i

=>

11i