Question

4 4.8 kg of potatoes and 5 kg of carrots cost $28
whereas 2 kg of potatoes and 3 kg of carrots
cost $1120. Find the cost of 1 kg of each item by substitution method?​

Answer 1

Answer:

Let pp be the cost per 1 kg of potatoes and cc be the cost per 1 kg of carrots.

8 kg of potatoes and 5 kg of carrots cost $28 so:

8p+5c=28 (1)

8p+5c=28(1)

2 kg of potatoes and 3 kg of carrots cost $11.20 so:

2p+3c=11.20 (2)

2p+3c=11.20(2)

Solve by elimination. Here, I decided to eliminate pp first. Multiply (2) by 4 to obtain (3):

8p+12c=44.80 (3)

8p+12c=44.80(3)

Subtract each side of (1) and (3) to eliminate pp and solve for cc:

−7c=−16.80

−7c=−16.80

c=2.40

c=2.40

Solve for pp using (1):

8p+5(2.40)=28

8p+5(2.40)=28

8p+12=28

8p+12=28

8p=16

8p=16

p=2

p=2

So, 1 kg of potatoes cost $2 while 1 kg of carrots cost $2.40.

Answer 2

Answer:

This is a wrong question