Question

4. 4. A car initially at rest starts moving with a constant acceleration of 0.5m/s2 and travels a distance of 25 m. The final velocity of the car is a. 10 m/s b. 5 m/s c. 15 m/s d. 8 m/s​

Answer 1

Answer:

Given :-

• A car initially at rest starts moving with a constant acceleration of 0.5 m/s2 and travels a distance of 25 m.

To Find :-

• What is the final velocity of the car.

Formula Used :-

$\clubsuit$ Third Equation Of Motion Formula :

$\mapsto \sf\boxed{\bold{\pink{v^2 =\: u^2 + 2as}}}$

where,

• v = Final Velocity
• u = Initial Velocity
• a = Acceleration
• s = Distance Covered

Solution :-

Given :

• Initial Velocity (u) = 0 m/s
• Acceleration (a) = 0.5 m/s²
• Distance Covered (s) = 25 m

According to the question by using the formula we get,

$\longrightarrow \sf v^2 =\: (0)^2 + 2(0.5)(25)$

$\longrightarrow \sf v^2 =\: 0 \times 0 + 2 \times 0.5 \times 25$

$\longrightarrow \sf v^2 =\: 0 + 1 \times 25$

$\longrightarrow \sf v^2 =\: 0 + 25$

$\longrightarrow \sf v^2 =\: 25$

$\longrightarrow \sf v =\: \sqrt{25}$

$\longrightarrow \sf\bold{\red{v =\: 5\: m/s}}$

${\small{\bold{\underline{\therefore\: The\: final\: velocity\: of\: the\: car\: is\: 5\: m/s\: .}}}}$

Hence, the correct options is option no (b) 5 m/s.

Answer 2

Answer:

Option b) 5 m/s is the correct answer.

Explanation:

Given,

$\bf \odot \: initial \: velocity \: \: u = 0 \: \: \: \: \pink{ \{ \: at \: rest \: \}} \\ \bf \odot \: acceleration \: \: \: a = 0.5 \: m {s}^{ - 2} \\ \bf \odot \: distance \: \: \: s = 25 \: m \\ \\ \green{ \bf \odot \: final \: velocity \: \: \: v = \: to \: find \: } \\ \\ \bf \: we \: know \: that \\ \\ \bf \: \: \: \: \: {v}^{2} = {u}^{2} + 2as \\ \bf \implies \: {v}^{2} = {0}^{2} + 2 \times 0.5 \times 25 \\ \bf \implies \: {v}^{2} = \cancel 2 \times \frac{1}{ \cancel2} \times 25 \\ \bf \implies \: {v}^{2} = 25 \\ \bf \implies \:v = \sqrt{25} \\ \bf \implies \:v = 5 \: m {s}^{ - 1} \\ \\ \green{ \boxed{\bf \: so \: final \: velocity \: \: v = 5 \: m {s}^{ - 1} }}$