Question

4
4. A pear costs x cents. An orange costs y cents less
than a pear. Find the cost of 4 pears and half a
dozen of oranges.

Answer 1

$4 \times 12 = 48 \\ the \: cost \: of \: 4 \: pears \: and \: half \: dozen \: of \: oranges$

Answer 2

Correct answer:-

Cost of a pear=x cents.

Cost of an orange=(x-y) cents.

Cost of 4 pears=4x cents.

Half a dozen means 6 oranges..

Cost of 6 oranges=6(x-y) cents

Total cost=Cost of 4 pears+Cost of 6 oranges=4x+6(x-y)=4x+6x-6y=10x-6y.

Hence, the cost of 4 pears and half a dozen of oranges is = 10x-6y cents.

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