4.4 gm of an unknown gas occupies 2.24 litre of
volume of STP. The gas may be
a. Carbon dioxide b. Carbon monoxide
c. Oxygen d. Sulphur dioxide
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Answer:
At STP 22.4L of any gas (assuming its ideal nature)≡ 1g-molecular i.e. 1mole of that gas
here 2.24 L of volume at STP ≡ 4.4g
∴ 22.4L of volume at STP ≡ 44g
So, molecular mass of the gas is 44g/mol
The gas may be CO2, C3H8(Propane)
hence, option (a) is correct
Explanation:
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