Question

4.4 gm of Co2 and 11.2 L of O2 are mixed in a container at stp. Find the partial pressure of O2 ?(ans is 0.83)

Answer 1

Given info : 4.4 g of CO2 and 11.2 L of O2 are mixed in a container at STP.

To find : the partial pressure of O2.

solution : given mass of CO2 = 4.4g

molecular mass of CO2 = 44g/mol

so no of moles of CO2 = 4.4/44 = 0.1

similarly, given volume of O2 = 11.2 L

so no of moles of O2 = given volume/22.4 L

= 11.2/22.4 = 0.5

so mole fraction of O2 = no of moles of O2/total moles

= 0.5/(0.5 + 0.1) = 5/6 = 0.83

now partial pressure of O2 = total pressure × mole fraction of O2

here at STP, total pressure = 1 atm

so, partial pressure of O2 = 1 × 0.83 = 0.83 atm

Therefore the partial pressure of O2 is 0.83 atm.

Answer 2

Answer:

Hope it help you

Have a good day