Question

4.4 kg of carbon dioxide gas, CO2, undergo isothermal expansion at 298 K from a volume of 2to 5 m3in three steps of 1 m3.Assumingideal gas behavior, what is the total work performed by the gas?

Answer 1

Answer:

I don't know the answer but sorry

Answer 2

Given,

Mass of the CO₂ gas (m) = 4.4g

Temperature (T)=298 K

Volume (V1) = 2 m³

Volume, (V2)= 5 m³

To find,

Total work performed by the gas (W)

Solution,

As it is given the CO₂ gas undergoes isothermal expansion.

Using the formula,

Work performed by the gas (W) = $NkTln(\frac{V_{2} }{V_{1} } )$

Number of moles in 4.4 g of CO₂=44 g/moles

∴N=44

On substituting the values, we get,

Work performed by the gas (W) = (44)(1.38×$10^{-23}$)(298)$ln\frac{5}{2}$

⇒W=44×1.38×$10^{-23}$×298×0.92

⇒W=16646×$10^{-23}$J

Hence, the total work performed by the gas is 16646×$10^{-23}$J