Question

4-4 sino = ????????????​

Answer 1

Correct option is

A

3

2π

​

 

Given, f(θ)=4+4sin  

3

θ−3sinθ

=4−(3sinθ−4sin  

3

θ)

=4−sin3θ

∴f(θ)=4−sin3θ

and f(θ+  

3

2π

​

)=4−sin[3(θ+  

3

2π

​

)]

      =4−sin(3θ+2π)=4−sin3θ

Hence, f(θ) is periodic with period  

3

2π

​