Question

4,40,667 ÷1000 what will be the remainder​

Answer 1

Answer:

Let the first odd number = x

Second odd number = x+2

And the third odd number = x+4

According to the condition,

x+x+2+x+4=63

\Rightarrow3x+6=63

⇒3x=63-6

⇒3x=57

⇒x=\frac{57}{3}

⇒x=19

∴ First odd number = x = 19

Second odd number = x + 2 = 19 + 2 = 21

third odd number = x + 4 = 19 + 4 = 23

Hence, the three consecutive odd numbers are 19, 21 and 23.

Step-by-step explanation:

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