Question

4.450 g of pure solute (molecular weight 98)were dissolved in 82.20 g of water. the density of the solution was fount to.be 1.029 g cm-3 at 25 degree celsius and 1 atm. calculate molality of the solute in the solution​

Answer 1

Explanation:

per sulphuric acid was added towater and the density of the solution was found to beatand 1 atm pressure. Calculate (a) the weight percent, (b) the mole fraction, (c) the mole percent, (d) the molality, (e) the molarity of sulphric acid in the solution under these conditions .



Text Solution

Solution :

Sulphuric acid

Water

<br>

<br> (a) Weight percent

<br> (b) Mole fraction : <br> Mole of solute

<br> Mole of solvent

<br> Total moles in solution

<br> Mole fractions of solute

<br> (c) Mole percent

<br> = mole fractions of solute

<br> (d) Molality =

<br> (e) Molarity

<br> Volume of solution

<br>

litre <br> Molarity

.



Answer

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Updated On: 17-6-2020

Answer 2

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