Chemistry, asked by shilpasravanthi, 4 months ago


4.48 L of methane at S.T.P. corresponds to
(A) 1.2 x 1022 molecules of methane
(B) 0.5 mole of methane
(C) 3.2 g of methane
(D) 0.1 mole of methane​

Answers

Answered by nandini566813
0

Answer:

u can solve it by ur self...the whole question...jo doubt h...aap vo pucho iss question m....m apko explain krdungi

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