Question

4.4g of an unknown gas occupies 2.24litres of volume at STP , the gas may be;

Answer 1

1 mole of a pure gas at STP occupies 22.4 L

thus 0.1 mole of the gas will occupy 2.24L

Now 1 mole of gas weighs equal to it's atomic/molar mass mass. Also 0.1 mole of the gas weighs 4.4g (since 4.4g occupies 2.24L)

Thus atomic mass/molar mass of the gas = 4.4/0.1 = 44g/mol

Thus the gas may be CO2