Question

4.4g of co2 and 2.24 lit.of h2 stp are mixed in a container.The total number of molecules present in the container will be​

Answer 1

Mole = mass/molecular mass = Volume /22.4

For CO2, Molecular mass= 12+32 = 44g

Mole = 4.4/44 = 44/440 = 0.1 mole of co2

For H2

Mole = Volume /22.4

Mole = 2.24 / 22.4

Mole = 224×10^-2/224×10^-1

Mole = 1×10^-1 = 0.1 mole of H2

Also,

Mole = N/Na

For H2, No of molecules = 0.1Na

For co2, No of molecules = 0.1 Na

Total molecules = 0.1Na+ 0.1 Na = 0.2 Na

Therefore, total molecules are 0.2 Na