Question

4.4gram me co2 kitna molecules present hoga​

Answer 1

Answer:

Hey buddy!!

There will be 6.022 x 10^22 molecules of CO2

Explanation:

44g= 6.022 x 10^23 molecules of CO2

So, in 4.49 = 6.022 x 10 ^22 molecules

Hope it helps:)

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