Question

4≤4x-4≤12 solve the inequalities​

Answer 1

Answer:

$4 \leqslant 4x - 4 \leqslant 12 \\ adding \: 4 \: in \: each \: term \\ 4 + 4 \leqslant 4x - 4 + 4 \leqslant 12 + 4 \\ 8 \leqslant 4x \leqslant 16 \\ 2 \leqslant x \leqslant 4$

Answer 2

Hey mate,

4⩽4x−4⩽12

adding 4 in each term

4+4⩽4x−4+4⩽12+4

8⩽4x⩽16

2⩽x⩽4

Hope it helps.