Math, asked by seemarathi402, 4 months ago

(4×+5)^2-80×=(4×-5)^2

Answers

Answered by as6371815

Answer:

$( {4x + 5})^{2} - 80x = ( {4x - 5})^{2} \\ = > \: 16 {x}^{2} + 25 + 40x - 80x = 16 {x}^{2} + 25 - 40x \\ = > 16 {x}^{2} - 16 {x}^{2} + 25x - 25x - 40x + 40x = 0 \\ = > 0$

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(4×+5)^2-80×=(4×-5)^2​

Answers

(4×+5)^2-80×=(4×-5)^2