Question

4+5 +5 x underoot of 9

Answer 1

Answer:

24

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Given x = 9 + 4√5.

⇒ 4 + 5 + 2 * 2 * √5

⇒ (2)^2 + (√5)^2 + 2 * (2) * (√5)

It is in the form of a^2 + b^2 + 2ab = (a + b)^2.

⇒ (2 + √5)^2.

So, x = (2 + √5)^2.

Then, √x = (2 + √5).

Now,

= > \frac{1}{\sqrt{x}}=>

x

1

= > \frac{1}{(2 + \sqrt{5})} * \frac{(2 - \sqrt{5})}{(2 - \sqrt{5})}=>

(2+

5

)

1

∗

(2−

5

)

(2−

5

)

= > \frac{(2 - \sqrt{5})}{(2)^2 - (\sqrt{5})^2}=>

(2)

2

−(

5

)

2

(2−

5

)

= > \frac{2 - \sqrt{5}}{4 - 5}=>

4−5

2−

5

= > \frac{2 - \sqrt{5}}{-1}=>

−1

2−

5

= > \sqrt{5} - 2=>

5

−2