Question

4/5,a,2 are 3 consecutive terms of A.P. find value of a

Answer 1

Since 4/5, a and 2 are consecutive parts of an AP, their common difference must be same

Therefore, a3 - a2 = a2- a1

2- a = a- 4/5
2-a= ( 5a - 4) / 5
5( 2-a ) = 5a - 4
10 - 5a = 5a - 4
14= 10 a
a= 14/10 = 7/5

Answer= 7/5